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What are the discontinuities of a function?
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\[f(x) = \frac{x^2-16}{6x-24}\]
Discontinuities will arise when the denominator goes to zero. What value of x will cause the denominator to go to zero.
4?
You have changed the denominator. In the original posting it is 6x-24. In your drawing it is 4x - 24. Which is the correct question?
Find when the denominator becomes 0. 4x - 24 = 0 4x = 24 x = 6. If x = 6, the denominator will become 0. There is a discontinuity at x = 6. The domain of this function excludes x = 6. x should not be 6.
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