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express y in terms of x if x/4-3y=7
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x/4=7+3y x/4-7=3y x/12-7/3=y
set y by itself by first adding over 3y to the other side once done subtract the seven over and then divide by 3 so it should look like\[(\frac{ x }{ 4 }-7)\ (\frac{ 1 }{ 3 })\]
multiply that through and you get\[\frac{ x }{ 12 }-\frac{ 7 }{ 3 }\]
x4−3y = 7 ⇒−3y = 7−x4 ⇒−3y = 28−x4 ⇒(−3y)×4 = 28−x ⇒−12y = 28−x ⇒−y = 28−x12 ⇒y = −(28−x12) ⇒y = x−2812 Therefore the required expression on terms of x is y = x−2812.
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