Implement the following with minimum number of 2 input LUTs F(a,b,c,d) = sum of m(0,1,3,6,8,9,14,15)... how to do this..pls guide quick
what is a LUT ?
fpga lookup table
so basically you want to minimize it first, and use only 2 input gates to implement Is that right ?
that i know.....but anything else i dont know about LUT CLB interconnections????? this is not that basic combinatorial circiit implementation. its FPGA related
me neither, sorry :(
If you want to implement it using 2 input gates, u may simplify it to : b'(c'+a'd') + bc(a+d')
other than that, idk how fpgas work in general. cant help sorry :/
http://www.eecg.utoronto.ca/~jayar/ece241_06F/solved35678.pdf reading this one page 8...gettin some idea
anyways thanks
so a 2 input LUT is a 2x1 multiplexer gate is it ?
hmmm....
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