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can someone help me i know my answer i just dont understand the last step to getting my answer . Use the quadratic formula to solve 2y2 – 6y – 8 = 0.
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2y2 – 6y – 8 = 0 is a formula in the form of ax^2 + bx + c = 0
\[\large x_{1,2}=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
that's the quadratic formula, you just need to fill in the a, b and c and you'll get the two answers
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