Question

A 42kg seal slides down a ramp into a pool. The top of the ramp is 1.75m higher than the surface of the water, and the ramp is inclined 35 degrees above the horizontal axis. If the seal reaches t

Answer 1

the text is incomplete, but from what you typed i guess this is probably a problem of conservation of energy, in that case:

\[mgh = \frac{ 1 }{ 2 }*m*v^2 => v=\sqrt{2gh} \\ d=\frac{ h }{ \sin \theta }\]

v=velocity when the seal touches water
d=distance before it its the water
h=1.75
theta=35*pi/180

with some kinematics you can derive time taken as well
but again the text was incomplete, so i probably answered in a wrong way!