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Mathematics 9 Online
OpenStudy (anonymous):

Brandon found that a solution of x = 1 was extraneous for his function. What would be a possible denominator in Brandon's function? 2x + 4 x2 + 3x + 9 3x - 11 x2 + 3x - 4

OpenStudy (p0sitr0n):

x=1 must be a root of the denominator. since the denominator cannot be zero, it is undefined at this point. seems like x2+3x-4=1+3-4=0 is the equation that youre looking for

OpenStudy (anonymous):

thank you :)

OpenStudy (p0sitr0n):

no prob

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