Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x^2 – 6x + 1 = 0


three real-number roots
two real-number roots
one real-number root
no real-number roots

Answer 1

find \(b^2-4ac\) with \(a=3,b=-6,c=1\)

Answer 2

one real-number root?

Answer 3

lets see
\[(-6)^2-4\times 3\times 1=36-12=24\] a positive number
so two real roots