The length of a football field is 67 yards greater than the width. The perimeter of the field is 346 yards. Find the length and width of the football field.
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OpenStudy (anonymous):
Lenght times Width easy as that
OpenStudy (anonymous):
how do i find the width?
OpenStudy (anonymous):
width is 53 and length is 120
OpenStudy (anonymous):
so i would take the 346 and divide by 67 and that would give me the length?
OpenStudy (anonymous):
no i will show you to width
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geerky42 (geerky42):
We are given that L = 67+W and P = 346.
Knowing that P = 2L + 2W, we can replace L to (67 + W) and P to 346, like this:
P = 2L + 2W
346 = 2(67+W) + 2W
Can you find W?
OpenStudy (anonymous):
take the 53 and add 67 and that would make it 120?
OpenStudy (anonymous):
yes! i see it! :D
geerky42 (geerky42):
Where did you get 53?
OpenStudy (anonymous):
let width is x ok
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OpenStudy (anonymous):
therfor length is x+67
OpenStudy (anonymous):
as we know perimeter = 2(l+b)
OpenStudy (anonymous):
put values of length and width here
OpenStudy (anonymous):
so 2(x+67) +2x
OpenStudy (anonymous):
=346
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geerky42 (geerky42):
yes
OpenStudy (anonymous):
346= 2(x+x+67)
346=4x+134
geerky42 (geerky42):
then solve for x.
OpenStudy (anonymous):
so the length is 134 and the width is 53. because when i solved for x i got 53
OpenStudy (anonymous):
346-134=4x
212=4x
212/4=x
53=x
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OpenStudy (anonymous):
i tried to check my answer with 2L+2W and i got 374 though?
OpenStudy (anonymous):
recheak
OpenStudy (anonymous):
134 x 2=268
53 x 2= 106
106+268=374
OpenStudy (anonymous):
53+67 = 120 not 134
OpenStudy (anonymous):
oh x) i had to go back and look at the work i see it now
120 x 2=240
53 x 2=106
240+106=346