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solve tan(x)(tanx+1)=0
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tan x = 0 and tanx+1 = 0, this is true at x = 0 and x = 135. (Quadrant ASTC negative at 45*3, use trigonometric table for reference.
tan x*(tan x + 1) = 0 If the chosen interval is (0 < x < 2Pi) then, the answers are: 1) tan x = 0 -> x = 0 and x = Pi 2) tan x = -1 -> x = 3Pi/4 and x = 7Pi/4
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