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what is the equation of the line that passes through (0, 4) and has a slope of -3
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Use the point-slope formula \(\large y-y_{1}=m(x-x_{1})\)
or just use y = mx + b y = mx + b slope(m) = -3 (0,4) x = 0 and y = 4 now sub 4 = -3(0) + b 4 = 0 + b 4 = b so your equation is : y = -3x + 4
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