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2 divided by the 6th root of 27
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\[\frac{ 2 }{ \sqrt[6]{27} }\]
\[\frac{ 2 }{6\sqrt{27}? }\]
\[\frac{ 2 }{ \sqrt[6]{27} }\]\[\frac{2}{\sqrt[6]{3^{3}}}\]\[\frac{2}{\sqrt{3}}\]
Or, another way: \[\frac{2}{\sqrt[6]{27}}\]\[\frac{2}{27^{\frac{1}6}}\]\[\frac{2}{(3^{3})^{\frac{1}6}}\]\[\frac{2}{3^{\frac{1}{2}}}\]\[\frac{2}{\sqrt{3}}\]
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yes i am new to this website so i was confused for a sec i was doing it off my phone
mari girl it is the first one you sent me ! :)
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