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Mathematics 11 Online
OpenStudy (anonymous):

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OpenStudy (ranga):

v1 = (1,6) and v2 = (5,-3) Sketch v1, v2, v1 + v2, v1 – v2, and v2 – v1

OpenStudy (ranga):

v1 = (1, 6) = i + 6j V2 = (5, -3) = 5i - 3j v1 + v2 = (i + 6j) + (5i - 3j) = 6i + 3j = (6, 3) v1 - v2 = (i + 6j) - (5i - 3j) = -4i + 9j = (-4, 9) v2 - v1 = -(v1 - v2) = 4i - 9j = (4,-9)

OpenStudy (ranga):

|dw:1397625717474:dw|

OpenStudy (ranga):

I am redoing the first problem here because the arrows were missing: |dw:1397629077245:dw|

OpenStudy (ranga):

OC is the graphical representation of the scalar projection of OA (5,3) onto OB (7,-2). OC = ( OA dot OB) / |OB| You can sub the numbers and find OC if necessary. But in the message you said you wanted just the graphical representation and it is as shown above.

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