Mathematics
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OpenStudy (anonymous):
LOOK AT ATTACHMENT
MEDAL+ FAN
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OpenStudy (anonymous):
OpenStudy (anonymous):
ok but how u did cross multiplication
OpenStudy (anonymous):
there is an = between two fractions
OpenStudy (anonymous):
thats how my teacher put the problem on the paper
OpenStudy (anonymous):
ok let me check
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OpenStudy (anonymous):
ya sorry its my mistake we can cross multiply is and in the third step it became a quadratic equation so if we solve it we r getting x=5 and 3
OpenStudy (anonymous):
so A is right
OpenStudy (anonymous):
Yeah, sheelo_mughal's on point. A is TRUE :)
OpenStudy (anonymous):
because whenever u solve quadratic equation u must get two values of x
OpenStudy (anonymous):
okay
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OpenStudy (anonymous):
even if u solve it using quadratic formulae u will get the same answer
OpenStudy (anonymous):
thanks for the medal @d3Xter
OpenStudy (anonymous):
can you help me with another problem @sheelo_mughal
OpenStudy (anonymous):
ya ofcourse
OpenStudy (anonymous):
welcome, sheelo_mughal :)
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OpenStudy (anonymous):
@sheelo_mughal
OpenStudy (anonymous):
2(x-2)=8
2x-4-4x=8
2x-4x-4=8
-2x-4=8
OpenStudy (anonymous):
C is the answer
OpenStudy (anonymous):
because if u subtract 2x-4x u'll get -2x
OpenStudy (anonymous):
@Ambbiiee
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OpenStudy (anonymous):
okay thank you
OpenStudy (anonymous):
The only solution is x=5. x=3 is out of domain.
OpenStudy (anonymous):
did u understand it
OpenStudy (anonymous):
kind of im starting to get an understanding @sheelo_mughal
OpenStudy (anonymous):
ok if u dont then can i explain u again
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OpenStudy (anonymous):
i got a B- on that problem so i did something right (: @sheelo_mughal