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Can someone explain how to solve this equation??? Medals will be given log 2 + log(4x - 1) = 3
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i hope you know the properties of log .. log m + log n = logmn
i kinda do
use it u will get log (8x -2)= 3 sice base is 10 .. so. 10^3= 8x -2
Can you explain how you got that answer?
@ankitshaw
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log(8x-2) = \[\log_{10}(8x-2) \] we know that \[a^b = c \] can be written as \[\log_{a} c =b\]
i hope now u will have no problem solving
Thank you :)
welcome
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