Question

What is the domain of the function y = sqrt3x + 3?

Answer 1

its \(\Large \sqrt{3x+3}\)
?

for the domain to be of real numbers, the quantity under the square root sign must be non-negative,
so, solve \(\Large 3x+3 \ge 0\)
to get your domain :)

Answer 2

The domain is \[[\infty,-1]\]