**HELP! SUCK AT PHYSICS & NEED HELP WITH THIS REVIEW QUESTION**
If 50 g of liquid water [C = 4,180 J/(kgK)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred?
A) 10.5 J

B) 10.5 kJ

C) 72.7 J

D) 100 kJ

Question

**HELP! SUCK AT PHYSICS & NEED HELP WITH THIS REVIEW QUESTION** 
 If 50 g of liquid water [C = 4,180 J/(kgK)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred?
        A) 10.5 J

B) 10.5 kJ

C) 72.7 J

D) 100 kJ

isaiah.feynman · Answer

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anonymous · Answer

Q is the heat added to the system. 

c is the specific heat (as given in the problem statement)

m is the mass of the water in kg. You're going to need to convert here. Notice the units on the specific heat value are given in kg. These need to match. 

$\Delta$T is the change in temperature in degrees Kelvin.

isaiah.feynman · Answer

Thank you @eashmore

anonymous · Answer

So I would multiply C*M then divide by the change in temperature?! @Isaiah.Feynman @eashmore

anonymous · Answer

Q= 0.05*(348-298)*4180
Q=10450
b)10.5 kJ