OpenStudy (anonymous):

**HELP! SUCK AT PHYSICS & NEED HELP WITH THIS REVIEW QUESTION** If 50 g of liquid water [C = 4,180 J/(kgK)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred? A) 10.5 J B) 10.5 kJ C) 72.7 J D) 100 kJ

OpenStudy (isaiah.feynman):

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OpenStudy (anonymous):

Q is the heat added to the system. c is the specific heat (as given in the problem statement) m is the mass of the water in kg. You're going to need to convert here. Notice the units on the specific heat value are given in kg. These need to match. $$\Delta$$T is the change in temperature in degrees Kelvin.

OpenStudy (isaiah.feynman):

Thank you @eashmore

OpenStudy (anonymous):

So I would multiply C*M then divide by the change in temperature?! @Isaiah.Feynman @eashmore

OpenStudy (anonymous):

Q= 0.05*(348-298)*4180 Q=10450 b)10.5 kJ