**HELP! SUCK AT PHYSICS & NEED HELP WITH THIS REVIEW QUESTION** If 50 g of liquid water [C = 4,180 J/(kgK)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred? A) 10.5 J B) 10.5 kJ C) 72.7 J D) 100 kJ
Q is the heat added to the system. c is the specific heat (as given in the problem statement) m is the mass of the water in kg. You're going to need to convert here. Notice the units on the specific heat value are given in kg. These need to match. \(\Delta\)T is the change in temperature in degrees Kelvin.
Thank you @eashmore
So I would multiply C*M then divide by the change in temperature?! @Isaiah.Feynman @eashmore
Q= 0.05*(348-298)*4180 Q=10450 b)10.5 kJ