Question

integral problem below!
help please been stuck on it..

Answer 1

to get from acceleration to velocity you need to integrate

Answer 2

to get from velocity to position you need to integrate

Answer 3

30t+4
=15t^2+4t
=5t^3+2t^2

Answer 4

@myininaya

Answer 5

you integrated acceleration but you forgot to put the constant

Answer 6

15t^2+4t+c
5t^3+2t^2+c

Answer 7

you integrate a constant
you constant*x+d
where d is another constant

Answer 8

I'm confused?

Answer 9

\[a(t)=30t+4 ; v(t)=15t^2+4t+C ; s(t)=5t^3+2t^2+Cx+D \]

Answer 10

example about integrating constant:
\[\int\limits_{}^{}5 dx=5x+c \]

Answer 11

so after intergrating to get s(t) do I plug 12 into t? @myininaya

Answer 12

you are given s(0)=16
this means to replace t with 0 and s with 16

you are also given v(0)=16
this means replace t with 0 and v with 16 <--do this v part first so you can find C

then do that first thing I have listed last to find D

Answer 13

find C first
do v(0)=16 to get C

Answer 14

\[v(t)=15t^2=4t+C\]

Answer 15

\[v(0)= \]
\[16=16(0)^2+4(0)+C\]
\[C=16\]
?

Answer 16

Yep
ok so now you know what C is
find D using s(0)=16

Answer 17

\[S(0)=\]
\[16=5(0)^3+2(0)t^2+16(0)+D\]
D=16?

Answer 18

yep
now you are ready to find s at t=12

Answer 19

\[S(16)=5(16)^3+2(16)^2+16(16)+16\]
\[S(16)=21264\]

Answer 20

@myininaya

Answer 21

so you know the question is asking what is s when t=12
not t=16

Answer 22

ohhh, awkward. but did I get the right concept?

Answer 23

lol yes

Answer 24

9136?

Answer 25

haha okay! thank youuuu!!!! (:

Answer 26

i could check that using a calculator
one sec

Answer 27

okay!

Answer 28

looks good

Answer 29

good job

Answer 30

thank you!