Question

find the equation of a tangenet line when y=8^x at x=1

Answer 1

write 8 as \( e^{\ln(8)} \)
so that your equation is
\[ y = e^{\ln(8)x} \]
find the slope dy/dx at x=1

Answer 2

After finding dy/dx then you would plug that into the line slope equation of (y-yo)=m(x-xo) where m=dy/dx. Right? I am learning too.

Answer 3

@Merlined
yes, with (x0, y0) = (1,8)
Here is a plot