Question

A ball is thrown straight upward from ground level with a velocity of 18m/s How much time passes before the ball strikes the ground? Disregard air resistance.

Answer 1

This is a perfect application for this equation:\[y=y _{0}+v _{0}t-\frac{ 1 }{ 2}g t ^{2}\]where y is the final height; y0 is the initial height; v0 is the initial velocity; t is time; and g is the acceleration of gravity.