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factor the trinomial completely r^2-14r+33
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find two numbers that multiply to 33 (last term) and add to -14 (middle coefficient)
i got (r+11)(r-3)
that is incorrect
notice how +11*(-3) = -33 but we should have +33
so both have to be addition
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the two numbers both have to be negative (since negative times negative = positive)
they have to negative because the middle coefficient is something negative while the last term is positive
what two negative numbers multiply to 33 ?
11 and 3
I think you mean -11 and -3
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so r^2-14r+33 factors to (r-11)(r-3)
notice how -11*(-3) = +33 and -11 + (-3) = -14
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