find f'(-2) if f(x)=(x+2)(x+3)(x+4)^2
the otherqoustion i have is
find the volume if the graph of y= √20/π e^x/2 is routated about the x-axis from x=ln(1/2) to x=0

Question

find f'(-2) if f(x)=(x+2)(x+3)(x+4)^2
the otherqoustion i have is 
find the volume if the graph of y= √20/π  e^x/2 is routated about the x-axis from x=ln(1/2) to x=0

ranga · Answer

f(x) = (x+2)(x+3)(x+4)^2 = (x^2 + 5x + 6) * (x + 4)^2
Use product rule to find f'(x).
Then put x = -2.

kc_kennylau · Answer

This is a step-by-step proof of the formula for the volume by rotation: http://www.wyzant.com/resources/lessons/math/calculus/integration/finding_volume

kc_kennylau · Answer

Basically it's just $\pi\int ydx$

anonymous · Answer

thanks kc-kennylau