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Chemistry 13 Online
Parth (parthkohli):

@gudden

OpenStudy (gudden):

Arey yaar chemistry me mat daal @aravindg firse delte karde ga..:p

Parth (parthkohli):

how to calculate the number of moles?

Parth (parthkohli):

I'm typing the exact question, wait a sec.

OpenStudy (gudden):

o.O the question ? :p

Parth (parthkohli):

OK, what's your question?

OpenStudy (gudden):

hold on! If \[\frac{ x }{ a } = \frac{ y }{ b } = \frac{ z }{ c }\]

OpenStudy (gudden):

@aravindg plz don't delete the question this time...! Am gonna post it...now...:'(

Parth (parthkohli):

I'm about to ask a chemistry question.

OpenStudy (aravindg):

I can understand the situation. But someone is trying to act over smart and that person needs to change their behavior.

OpenStudy (aravindg):

Do not worry I will not delete the thread. But trying to make us moderators believe that you are discussing a Chemistry question here is a bad idea. With that in mind get your help :)

OpenStudy (gudden):

\[\frac{ x ^{3} + a ^{3} }{ x ^{2} + a ^{2}} + \frac{ y ^{3} + b ^{3}} {a ^{2} + b ^{2} } + \frac{ z ^{3} + c ^{3}}{ z ^{2} + c ^{2} } = \frac{ (x+y+z)^{3} + (a+b+c)^{3} }{ (x+y+z)^{2} +(a +b+c)^{2} }\] finally

OpenStudy (gudden):

sure @ParthKohli ... yaar himmat nahi hai.. firse likhne ki :p

OpenStudy (gudden):

can you do it BTW ?

Parth (parthkohli):

I hope I can. I've done a question similar to this one.

Parth (parthkohli):

I've tagged you in a relevant group so we may take our discussions there...

OpenStudy (gudden):

Sure!!

OpenStudy (gudden):

Anyone willing to help is welcomed :) @ilovebmth1234 @ikram002p @hartnn ( and all others, willing to help are also invited....:) ) well.. I tried posting the image of the question in here by the Attach File option, but I failed twice... + I also tried The DRAW tool...and failed there too..! Anhaaan! My ID is sorta, Little mess..:) so, open in here ....=> http://www.twiddla.com/1586862 for the question..!

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