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Find the LCM: x^2-9 and 3x-9
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help!!!
??????
3(x-3)(x+3) is divisible by both of those and there is nothing small that is divisible by both.
'small' should have been 'smaller' in previous post
huh
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x² - 9=(x-3)(x+3) 3x - 9=3(x-3) so the LMC (not just least, the only one) is (x-3)
thats it
1) 3(x - 3) 2) 3(x + 3) 3) 3(x -3)(x + 3) 4) (x - 3)(x + 3)
are these 1, 2, 3 the options or what ?
options i have o choose from
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to
Well, none of these options are the LMC of x²-9 and 3x-9
I beg to differ. The LMC is number 3.
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