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Verify the identity. cotx minus pi divided by two. = -tan x
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\[\cot \left( x-\frac{ \pi }{ 2 } \right)=-\tan x\]
@Luigi0210
yay :D
It's an identity.. just take out the negative.
so cot(x+\pi\2)=tanx
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\[-\cot \left( \frac{ \pi }{ 2 }-x \right)=-\tan x\] \[-(tanx)=-tanx \] \[-tanx=-tanx\]
you said take out the negative! and then you went and used negatives in every single one of those
Yea, factor it, don't kill it
what? how do even factor crap like... you turned an equation into -tanx, what?
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.-. why does math have to have so much hard stuffs
It's not hard really.
Just practice.
ugh .-. it is for me... too much memorizing stuff
Well better get started now if you're gonna move on in math c:
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yeah :c
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