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Mathematics 15 Online
OpenStudy (lovelyharmonics):

Verify the identity. cotx minus pi divided by two. = -tan x

OpenStudy (lovelyharmonics):

\[\cot \left( x-\frac{ \pi }{ 2 } \right)=-\tan x\]

OpenStudy (lovelyharmonics):

@Luigi0210

OpenStudy (lovelyharmonics):

yay :D

OpenStudy (luigi0210):

It's an identity.. just take out the negative.

OpenStudy (lovelyharmonics):

so cot(x+\pi\2)=tanx

OpenStudy (luigi0210):

\[-\cot \left( \frac{ \pi }{ 2 }-x \right)=-\tan x\] \[-(tanx)=-tanx \] \[-tanx=-tanx\]

OpenStudy (lovelyharmonics):

you said take out the negative! and then you went and used negatives in every single one of those

OpenStudy (luigi0210):

Yea, factor it, don't kill it

OpenStudy (lovelyharmonics):

what? how do even factor crap like... you turned an equation into -tanx, what?

OpenStudy (luigi0210):

http://www.sosmath.com/trig/Trig5/trig5/trig5.html

OpenStudy (lovelyharmonics):

.-. why does math have to have so much hard stuffs

OpenStudy (luigi0210):

It's not hard really.

OpenStudy (luigi0210):

Just practice.

OpenStudy (lovelyharmonics):

ugh .-. it is for me... too much memorizing stuff

OpenStudy (luigi0210):

Well better get started now if you're gonna move on in math c:

OpenStudy (lovelyharmonics):

yeah :c

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