Question

Given the quadratic equation, written in General/ vertex form, state/ discuss..
Y=3/4(x+2)^2-5

1) the vertex
2) opening up or down
3) wider or narrower comparing with y=x^2
4)Domain and range
5) axis of symmetry

PLEASE help!! this is a pre-test question I don't understand

Answer 1

@whpalmer4 can you help?

Answer 2

@kropot72 ? can you help

Answer 3

@Hero

Answer 4

If given a quadratic equation of the form y = a(x - h) + k, then
(h,k) is the vertex
\(a\) is positive, then the graph opens up
\(a\) is negative then the graph opens down
If \(0 < a < 1\) then the graph will be wider than y = x^2
If \(a > 1\) or \(a < -1\) then the graph will be narrower
The domain of a quadratic equation is always all real numbers
If the graph opens up then the range will be \(-b/(2a), \infty\)
If the graph opens down, then the range will be \(-b/(2a), -\infty\)

Answer 5

Thank you so much :D @Hero

Answer 6

Well, you still have to do the work. I was just giving you general info.