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The circle shown below has AB and BC as its tangents. If the measure of arc AC is 160°, what is the measure of angle ABC? 80° 40° 60° 20°
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i will fan and medal
There a (at least) 2 ways to get the answer: 1) remember the "rule" the exterior angle ABC = ½ (difference between intercepted arcs) 2) draw some radiuses (radii if you are Latin) like this |dw:1397764412274:dw|
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