What is the area of the sector bound by the center of the circle and arc CD in the circle below?
@ganeshie8
whats the area of total circle ?
it has a radius, r = 6 whats the area ?
\[A =\Pi(r)^{2}\] \[A =\Pi(6)^{2}\]
yes ! but u dont want the entire circle, u only want the area of 60 degree part
Since a circle has 360 degrees, to get the area of 60 degree part, u can simply multiply it by 60/360
So 113.04 * 60/360?
Oops ! wait, u want only 30 degree part right ?
So scratch the previous stuff. do below : Area of 30 degree part = \(\large \pi (6)^2 \times \dfrac{30}{360}\)
simplify
Sorry my computer is slow..... I got 9.42
thats right ! http://www.wolframalpha.com/input/?i=%5Cpi*%286%29%5E2+++%5Ctimes++%5Cdfrac%7B30%7D%7B360%7D
Thank you!
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