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If y varies directly as x, and y=10 when x=2.4, find x when y=15.
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Since "y varies directly as x", we know that y = k*x where k is some fixed number
we are told that "y=10 when x=2.4", so plug these values into the equation to get y = k*x 10 = k*2.4 now solve for k and tell me what you get
would k = 4.16?
roughly, yes
so your equation y = k*x updates to y = 4.16*x (approximately)
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once you know k, you can find x when given a certain value of y (or vice versa)
this time we need to find x when y = 15 y = 4.16*x 15 = 4.16*x x = ??
x=3.60
good, that is the correct answer
ok thank you so much!
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you're welcome
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