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Mathematics 7 Online
OpenStudy (anonymous):

which of the following are solutions to sinxcosx=-1/4? A. 7pi/6+npi B. 7pi/12+npi C. 7pi/12+npi/2 D. 11pi/12+npi

myininaya (myininaya):

recall sin(2x)=2sin(x)cos(x)

myininaya (myininaya):

So if we multiply 2 on both sides we have 2sin(x)cos(x)=-2/4 can you take it from here?

myininaya (myininaya):

by the by way you can reduce that one fraction and say 2sin(x)cos(x) is sin(2x)

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