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sin15*cos15 ( degrees)
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We have still not learnnt the half angle formulae so how to do it without that
Do you know double angle?
And the double angle formulas? Let\[k = \sin(15)\cos(15)\]But\[2k =2\sin(15)\cos(15) = \sin(30) = \dfrac{1}{2}\]\[\Rightarrow k = \dfrac{1}{4}\]
i know all of them actually but is there a way to solve it without them becoz in school we havent learnt them
Do you know trig?
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And geometry?
are u kidding @primeralph
I can't read your mind.
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