Question

passes through(4,2) and (3,-2)?show working

Answer 1

let points be (a1,b1)and (a2,b2)........then substitute in the formulae......y-a2=(b2-b1/a2-a1)(x-a2)............

Answer 2

is the question to find the gradient of the line that passes through those points?

Answer 3

if it is, then it's:

\[\frac{ 2-(-2) }{ 4-3 }\]

which simplifies to

\[\frac{ 4 }{ 1 }\]

which equals 4.

Answer 4

basically, to find the gradient of a line, you use the formula:

\[\frac{ y _{1}-y _{2} }{ x _{1} -x _{2}}\]