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OpenStudy (anonymous):
How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Show all of the work needed to solve this problem. Mg (s) + 2 HCl (aq) MgCl2 (aq) + H2 (g)
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OpenStudy (gebooors):
Calculate amount of substance of HCl. You get it n = c V Then you see Mg is needed half of moles of HCl. Then m(Mg) = n(Mg) * M(Mg)
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