Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x − ___

Answer 1

@hartnn @johnweldon1993 @myininaya @Preetha @texaschic101

Answer 2

since you have the x intercepts,
the constant part in the expression, \(y =ax^2+bx+c\)
which is '+c' ,
always equals the product of x-intercepts

Answer 3

so, what is \(-6 \times2 =...?\)

Answer 4

-12

Answer 5

@hartnn right?

Answer 6

yes
thats the constant part
so what will go in blank space ?? (considering you already have - *minus* outside the blank)

Answer 7

12?

Answer 8

correct! :)

Answer 9

Thank you @hartnn

Answer 10

welcome ^_^