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OpenStudy (anonymous):
A spinner is divided into 10 equal sections numbered from 0 to 10. You spin the spinner once. What is P(even)? a. 3/5 b. 1/2 c. 5/11 d. 6/11
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OpenStudy (anonymous):
If the spinner is numbered from 0 to 10 then it must have _11_ sections. There appears to be something wrong with the statement of this problem.
OpenStudy (anonymous):
That is exactly what it says on my homework.
OpenStudy (anonymous):
I think the answer is C
OpenStudy (anonymous):
Same here. The answer shouldbe C.
OpenStudy (bibby):
0 is an even number
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OpenStudy (anonymous):
Ohh yeah you're right :P thanks
OpenStudy (anonymous):
Even possibilities : 0, 2, 4, 6, 8, 10 (6 of them) Odd possibilities : 1, 3, 5, 7, 9, 11 (6 of them) P(even) = 1/2
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