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Find a polynomial function with the given zeros, 0,0,0,sqrt6, -sqrt6
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\[(x-0)(x-0)(x-0)(x-\sqrt{6})(x+\sqrt6)\]
Of course, \((x-0)(x-0)(x-0)=x^3\)
So would the answer be x^5-6x^3?
Yes, that is correct.
Yeah,,, thanks
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Here's a plot showing the axis crossings at the roots of odd multiplicity
even multiplicity gets you a touching of the axis, but not a crossing
vertical lines indicate \(x=\pm\sqrt{6}\)
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