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Mathematics 21 Online
OpenStudy (anonymous):

The box plots below show the lifespan, in months, of laptop batteries manufactured by two companies:

OpenStudy (anonymous):

OpenStudy (anonymous):

Based on the data, which company's batteries have the shortest average lifespan? Company A Company B Company C Company D

OpenStudy (anonymous):

@annas

OpenStudy (anonymous):

my answer is company A

OpenStudy (anonymous):

company A it is :)

OpenStudy (anonymous):

help me with another box plot question ?

OpenStudy (anonymous):

The heights, in cm, of some plants in a greenhouse are shown below: 13.5, 12.2, 12.8, 12.8, 12.3, 12, 13.9, 14, 14.2, 12.6 Jack made the following box plot to represent the heights:

OpenStudy (anonymous):

Which of the following did Jack show incorrectly on his box plot? Median Minimum First quartile Third quartile

OpenStudy (anonymous):

@annas is it first quartile ?

OpenStudy (anonymous):

this will be the right plot

OpenStudy (anonymous):

so my answer was correct ? first quartile ?

OpenStudy (anonymous):

I guess yeah :)

OpenStudy (anonymous):

you guess? Which of the following did Jack show incorrectly on his box plot? Median Minimum First quartile <-- my answer Third quartile

OpenStudy (anonymous):

its the right answer ?

OpenStudy (anonymous):

yeah it is the first quartile

OpenStudy (anonymous):

thank you.. i need help with this too The following histograms show the average number of hours two groups of students spend cycling every week:

OpenStudy (anonymous):

Which statement best compares the median number of hours that the two groups of students spend cycling every week? Median is between 4 and 5 hours for both groups. Median is between 5 and 6 hours for both groups. Median for group A is significantly less than the median for group B. Median for group A is significantly greater than the median for group B.

OpenStudy (anonymous):

my answer is B

OpenStudy (anonymous):

B it is "Median is between 5 and 6 hours for both groups."

OpenStudy (anonymous):

one more please The ages of some students who participated in an art camp are shown below: 10, 12, 10, 12, 7, 10, 9, 13, 16, 9, 10, 12, 15, 10, 16, 18, 15, 10, 15, 9 Which histogram best represents the data?

OpenStudy (anonymous):

OpenStudy (anonymous):

my answer is D

OpenStudy (anonymous):

wait a sec please

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

your answer

OpenStudy (anonymous):

is that D or is that the correct answer

OpenStudy (anonymous):

the graph you posted looks 100% different from the answer choices

OpenStudy (anonymous):

yes but its the correct answer

OpenStudy (anonymous):

so what is it ? A,B,C,D ?

OpenStudy (anonymous):

its close to D

OpenStudy (anonymous):

so is the answer D

OpenStudy (anonymous):

look at the pictures i uploaded ...

OpenStudy (anonymous):

wait lemme verify

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@bibby can you check this

OpenStudy (anonymous):

@Destinymasha

OpenStudy (anonymous):

..

OpenStudy (anonymous):

your options to last one confuses me

OpenStudy (anonymous):

@Squirrels

OpenStudy (anonymous):

me too

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

you're talking about those right

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

i was pretty sure it was D but your graph confused me /:

OpenStudy (anonymous):

@Luigi0210 dude check this last question

OpenStudy (anonymous):

thats what I said my graph is close to D

OpenStudy (anonymous):

ill just risk it /:

OpenStudy (anonymous):

can you help me on this last one ? The average number of emails received each day by two groups of people is shown below: Group A: 3, 2, 1, 1, 2, 4, 2, 2, 3, 3, 4 Group B: 4, 2, 200, 2, 2, 1, 2, 3, 1, 3, 3 Which statement best describes the mean and median of the data shown above? The median number of emails received by people of groups A and B is the same because the outlier does not affect the median. The median number of emails received by people of group B is higher because of the presence of an outlier. The mean number of emails received by people of group B is lower because of the presence of an outlier. The mean number of emails received by people of group A is higher because of the absence of an outlier.

OpenStudy (anonymous):

@annas ... ?

OpenStudy (anonymous):

I am sorry I was afk and dear girl this one is tricky

OpenStudy (anonymous):

please help me

OpenStudy (anonymous):

ok ok

OpenStudy (anonymous):

Group A: Total Numbers: 11 Mean (Average): 2.45455 Median: 2 Mode: 2 Group B: Total Numbers: 11 Mean (Average): 20.27273 Median: 2 Mode: 2

OpenStudy (anonymous):

so ...

OpenStudy (anonymous):

it would be A ?

OpenStudy (anonymous):

yup A

OpenStudy (anonymous):

wait what about C ?

OpenStudy (anonymous):

mean(A) < mean(B) 2.45455 < 20.27273

OpenStudy (anonymous):

so whats the final answer

OpenStudy (anonymous):

you know it :|

OpenStudy (anonymous):

A or C

OpenStudy (anonymous):

do you think C is right ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

explain how?

OpenStudy (anonymous):

no A

OpenStudy (anonymous):

i was curious about C

OpenStudy (anonymous):

then what is your final answer ? :/

OpenStudy (anonymous):

a

OpenStudy (anonymous):

good!

OpenStudy (anonymous):

and you are welcome @yeah_i_suck_at_math

OpenStudy (anonymous):

yes thank you

OpenStudy (anonymous):

@Luigi0210 you're late brah ! :/

OpenStudy (luigi0210):

Yea, usually AFK most of the time.

OpenStudy (anonymous):

its cool brah!

OpenStudy (anonymous):

can you guys please help me on my new question

OpenStudy (anonymous):

@yeah_i_suck_at_math umm sorry I'm afraid I can't :/

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