The box plots below show the lifespan, in months, of laptop batteries manufactured by two companies:
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OpenStudy (anonymous):
OpenStudy (anonymous):
Based on the data, which company's batteries have the shortest average lifespan?
Company A
Company B
Company C
Company D
OpenStudy (anonymous):
@annas
OpenStudy (anonymous):
my answer is company A
OpenStudy (anonymous):
company A it is :)
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OpenStudy (anonymous):
help me with another box plot question ?
OpenStudy (anonymous):
The heights, in cm, of some plants in a greenhouse are shown below:
13.5, 12.2, 12.8, 12.8, 12.3, 12, 13.9, 14, 14.2, 12.6
Jack made the following box plot to represent the heights:
OpenStudy (anonymous):
Which of the following did Jack show incorrectly on his box plot?
Median
Minimum
First quartile
Third quartile
OpenStudy (anonymous):
@annas is it first quartile ?
OpenStudy (anonymous):
this will be the right plot
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OpenStudy (anonymous):
so my answer was correct ? first quartile ?
OpenStudy (anonymous):
I guess yeah :)
OpenStudy (anonymous):
you guess?
Which of the following did Jack show incorrectly on his box plot?
Median
Minimum
First quartile <-- my answer
Third quartile
OpenStudy (anonymous):
its the right answer ?
OpenStudy (anonymous):
yeah it is the first quartile
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OpenStudy (anonymous):
thank you..
i need help with this too
The following histograms show the average number of hours two groups of students spend cycling every week:
OpenStudy (anonymous):
Which statement best compares the median number of hours that the two groups of students spend cycling every week?
Median is between 4 and 5 hours for both groups.
Median is between 5 and 6 hours for both groups.
Median for group A is significantly less than the median for group B.
Median for group A is significantly greater than the median for group B.
OpenStudy (anonymous):
my answer is B
OpenStudy (anonymous):
B it is "Median is between 5 and 6 hours for both groups."
OpenStudy (anonymous):
one more please
The ages of some students who participated in an art camp are shown below:
10, 12, 10, 12, 7, 10, 9, 13, 16, 9, 10, 12, 15, 10, 16, 18, 15, 10, 15, 9
Which histogram best represents the data?
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OpenStudy (anonymous):
OpenStudy (anonymous):
my answer is D
OpenStudy (anonymous):
wait a sec please
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
your answer
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OpenStudy (anonymous):
is that D or is that the correct answer
OpenStudy (anonymous):
the graph you posted looks 100% different from the answer choices
OpenStudy (anonymous):
yes but its the correct answer
OpenStudy (anonymous):
so what is it ? A,B,C,D ?
OpenStudy (anonymous):
its close to D
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OpenStudy (anonymous):
so is the answer D
OpenStudy (anonymous):
look at the pictures i uploaded ...
OpenStudy (anonymous):
wait lemme verify
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@bibby can you check this
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OpenStudy (anonymous):
@Destinymasha
OpenStudy (anonymous):
..
OpenStudy (anonymous):
your options to last one confuses me
OpenStudy (anonymous):
@Squirrels
OpenStudy (anonymous):
me too
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
you're talking about those right
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
i was pretty sure it was D but your graph confused me /:
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OpenStudy (anonymous):
@Luigi0210 dude check this last question
OpenStudy (anonymous):
thats what I said my graph is close to D
OpenStudy (anonymous):
ill just risk it /:
OpenStudy (anonymous):
can you help me on this last one ?
The average number of emails received each day by two groups of people is shown below:
Group A: 3, 2, 1, 1, 2, 4, 2, 2, 3, 3, 4
Group B: 4, 2, 200, 2, 2, 1, 2, 3, 1, 3, 3
Which statement best describes the mean and median of the data shown above?
The median number of emails received by people of groups A and B is the same because the outlier does not affect the median.
The median number of emails received by people of group B is higher because of the presence of an outlier.
The mean number of emails received by people of group B is lower because of the presence of an outlier.
The mean number of emails received by people of group A is higher because of the absence of an outlier.
OpenStudy (anonymous):
@annas ... ?
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OpenStudy (anonymous):
I am sorry I was afk and dear girl this one is tricky
OpenStudy (anonymous):
please help me
OpenStudy (anonymous):
ok ok
OpenStudy (anonymous):
Group A:
Total Numbers: 11
Mean (Average): 2.45455
Median: 2
Mode: 2
Group B:
Total Numbers: 11
Mean (Average): 20.27273
Median: 2
Mode: 2
OpenStudy (anonymous):
so ...
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OpenStudy (anonymous):
it would be A ?
OpenStudy (anonymous):
yup A
OpenStudy (anonymous):
wait what about C ?
OpenStudy (anonymous):
mean(A) < mean(B)
2.45455 < 20.27273
OpenStudy (anonymous):
so whats the final answer
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OpenStudy (anonymous):
you know it :|
OpenStudy (anonymous):
A or C
OpenStudy (anonymous):
do you think C is right ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
explain how?
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OpenStudy (anonymous):
no A
OpenStudy (anonymous):
i was curious about C
OpenStudy (anonymous):
then what is your final answer ? :/
OpenStudy (anonymous):
a
OpenStudy (anonymous):
good!
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OpenStudy (anonymous):
and you are welcome @yeah_i_suck_at_math
OpenStudy (anonymous):
yes thank you
OpenStudy (anonymous):
@Luigi0210 you're late brah ! :/
OpenStudy (luigi0210):
Yea, usually AFK most of the time.
OpenStudy (anonymous):
its cool brah!
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OpenStudy (anonymous):
can you guys please help me on my new question
OpenStudy (anonymous):
@yeah_i_suck_at_math umm sorry I'm afraid I can't :/