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How does the zero product property help you find the x-intercept of y = x² - x - 12?
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To find x intercept plug y = 0 into given equation So we get \[x^2-x-12=0\] Now use quadratic formula or AC method
Because if we can factor it into something like: \[ (x-a)(x-b) =0 \]Then if \(x-a=0\) the whole thing is zero. The same goes for \(x-b=0\).
Yes but before this we have to find out groups .....
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