I really need help with this question find the difference in the two surface areas of the two figures shown
the choices are provided in the image I tried to solve it but I didn't get the correct answer I guess
what was your answer?
I got 253.50
its not correct
OMG that is hard i dont know im sorry
its ok, nvm :) thanks for trying though :)
np
Since u need to find the height of both square pyramids. This website might help http://www.calculatorsoup.com/calculators/geometry-solids/pyramid.php.
The left is a square pyramid right?
Left one is a squared pyramid the right one is a rectangular pyramid
I got around 427 For the left, the base=144 And use pythagoereom theorem to find height of triangle, 6^2 + x^2 =15^2 and the height of triangle=3sqrt21 Then use it to find area of triangles 1/2 (12)(3sqrt21) x4(becuz there r 4 triangles) +144=SA of entire pyramid
Do the same on the right Base=288 For triangle with base 12 find the height using pyth. Again 6^2 +x^2 =20^2 x=2sqrt91 and use this to find area of the side triangles and get around 24sqrt91 Do the same for the front and back 12^2 +x^2 =20^2 x=16 And the area =1/2(16)(24) x2=384 Add them all up. 288+24sqrt91+384=SA of right pyramid And subtract this^ with what you got on the left and should get around 427
thank you so much for your help, this was really helpful t
thanks @nikato
No problem. Glad to help
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