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find cos (2sin^-1(5/7))
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Draw a triangle representing \(\sin^{-1}\dfrac57\) first
is it possible for someone to help break this problem down for me? i need to find the exact values. thanks in advance!
Kc_kennylau.. How do I draw a triangle with the sin^-1? does that come out to 1/sin?
First you have to know what \(\sin^{-1}\) means.
It does not mean \(\dfrac1\sin\), but instead it's the inverse function of \(\sin\)
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For example, if \(\sin30^\circ=0.5\), then \(\sin^{-1}0.5=30^\circ\)
Draw an right triangle where \(\sin\theta=\dfrac57\) first :)
awesome, going to do so now!!
Okay, and as always you can use the draw button below :)
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