Question

6(4z+3)-10(7z-1)=3(2-19z)
Solve for z

Answer 1

You have shared only one equation here, and that equation does not involve x at all. How, then, can you expect to solve for x and y?

Is it possible that there was another equation that should have come with this one?

Answer 2

Oh no,I had post a wrong equation,may I edit

Answer 3

type everything you have all over again, unless you know how to edit your previous post.

Answer 4

But I already edit before your replied,sorry I edit before your replied.

Answer 5

6(4z+3)-10(7z-1)=3(2-19z).

Multiply out each product. For example, 6(4z+3)=24z+18.

Answer 6

then group all the z terms on the left side and all the constants on the other side.

Answer 7

Is z=-2?

Answer 8

I need to see your actual work, if you want me to check your work.

Multiply out each product. For example, 6(4z+3)=24z+18.

Answer 9

6(4z+3)-10(7z-1)=3(2-19z)
=24z+18-70z+10=6-57z
=24z -70z+18+10=6-57z
=-46+28=6-57z
11z+28=6
11z=-22
z=-2

Answer 10

sorry I mean -46z

Answer 11

24z+18-70z+10=6-57z
-46z+28=6-57z
-46z+57z=6-28
11z=-22
Z=-2