Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − ___

Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of 
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.) 

y = x2 + 6x −  ___

loser66 · Answer

your attempt?

anonymous · Answer

Generally our vertex is ( ( -b/2a)  , f (( -b/2a)) ) we are given with vertex as ( -3 , -25) getting this?

anonymous · Answer

We are having x intercepts as x =-8 and x = 2  can you try to find out factors from it ?

anonymous · Answer

If we rewrite it as factors then we got  ( x + 8 )  and ( x - 2 )  Getting this ???

anonymous · Answer

Now just  multiply these factors to get quadratic equation   can you try for it ?3
( x + 8 ) ( x - 2 ) = ----- ?