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Mathematics 8 Online
OpenStudy (anonymous):

Find the length of the hypotenuse of QPO

OpenStudy (anonymous):

Where is diagram ???

OpenStudy (anonymous):

|dw:1398022406222:dw|

OpenStudy (anonymous):

@suyogsomavanshi

OpenStudy (anonymous):

Here we have to use pythagoras theorem Are you familiar with it ???

OpenStudy (anonymous):

yes A^2+B^2=C^2

OpenStudy (anonymous):

Correct so it is nothing but hypotenuse^2= one side ^2 + other side ^2 getting this ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

|dw:1398022811554:dw|

OpenStudy (anonymous):

Perfect now expand parentheses first ......

OpenStudy (anonymous):

would it be 2x+36=25+2x+25?

OpenStudy (anonymous):

You are not right for this We need to use formula \[( a+ b )^2= a^2+2ab+b^2\] Can you try now ?

OpenStudy (anonymous):

i dont understand this step

OpenStudy (anonymous):

okay we are having ( x + 6 )^2 correct ? Compare it with ( a + b )^2 so a = ---- ? b = --- ?

OpenStudy (anonymous):

so A=x and B=6

OpenStudy (anonymous):

correct now plug it into \[a^2+2ab+b^2\] can you try ?

OpenStudy (anonymous):

(x)^2+2*6x+6^2 x^2+12x+36

OpenStudy (anonymous):

Perfect ..... now can you try for ( x + 5 )^2 = ---- ?

OpenStudy (anonymous):

Hello ... are you working on it ?

OpenStudy (anonymous):

x^2+5x+5x+25?

OpenStudy (anonymous):

Correct try to simplify it .....

OpenStudy (anonymous):

x^2+10x+25

OpenStudy (anonymous):

Perfect so we get equation as \[x^2+12x+36=5^2+x^2+10x+25\] Getting this ?

OpenStudy (anonymous):

Now collect like terms ....

OpenStudy (anonymous):

2x+11=5x^2?

OpenStudy (anonymous):

you are not right please check it once

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