Mathematics
8 Online
OpenStudy (anonymous):
Find the length of the hypotenuse of QPO
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OpenStudy (anonymous):
Where is diagram ???
OpenStudy (anonymous):
|dw:1398022406222:dw|
OpenStudy (anonymous):
@suyogsomavanshi
OpenStudy (anonymous):
Here we have to use pythagoras theorem Are you familiar with it ???
OpenStudy (anonymous):
yes A^2+B^2=C^2
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OpenStudy (anonymous):
Correct so it is nothing but hypotenuse^2= one side ^2 + other side ^2 getting this ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
|dw:1398022811554:dw|
OpenStudy (anonymous):
Perfect now expand parentheses first ......
OpenStudy (anonymous):
would it be 2x+36=25+2x+25?
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OpenStudy (anonymous):
You are not right for this We need to use formula \[( a+ b )^2= a^2+2ab+b^2\]
Can you try now ?
OpenStudy (anonymous):
i dont understand this step
OpenStudy (anonymous):
okay we are having ( x + 6 )^2 correct ?
Compare it with ( a + b )^2 so a = ---- ? b = --- ?
OpenStudy (anonymous):
so A=x and B=6
OpenStudy (anonymous):
correct now plug it into \[a^2+2ab+b^2\] can you try ?
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OpenStudy (anonymous):
(x)^2+2*6x+6^2
x^2+12x+36
OpenStudy (anonymous):
Perfect ..... now can you try for ( x + 5 )^2 = ---- ?
OpenStudy (anonymous):
Hello ... are you working on it ?
OpenStudy (anonymous):
x^2+5x+5x+25?
OpenStudy (anonymous):
Correct try to simplify it .....
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OpenStudy (anonymous):
x^2+10x+25
OpenStudy (anonymous):
Perfect so we get equation as \[x^2+12x+36=5^2+x^2+10x+25\]
Getting this ?
OpenStudy (anonymous):
Now collect like terms ....
OpenStudy (anonymous):
2x+11=5x^2?
OpenStudy (anonymous):
you are not right please check it once