Question

The slope of the line tangent to the graph of

Answer 1

\[y=e^{\sqrt{x+1}}\]

Answer 2

at its inflection point is

Answer 3

first you need to find \(\Large y^{\prime\prime}\) (ie the second derivative)

Answer 4

yes so I can find the zero

Answer 5

my calculator is slow but I am working on it

Answer 6

then I take that value and input it into the first derivative

Answer 7

yes, that is correct

Answer 8

got it, thanks

Answer 9

you're welcome