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3^x=27^(x-4)
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\[3^x = 3^{3(x - 4)}\] \[x = 3(x - 4)\]
I need to know what x would be?
Solve for x
book says x=6 but I don't get that, could someone explain indetail
x = 3(x - 4) x = 3x - 12 12 = 3x - x 12 = 2x 12/2 = x 6 = x
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ok thanks I see it now.
yw
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