Question

xy=240, find x-y when x+y=32 and x>y can some one please provide the solution

Answer 1

Hint: Use the square of the functions.

Answer 2

\[(x+y)^2=x^2+2xy+y^2=32^2\] and \((x-y)^2=x^2-2xy+y^2\)

Answer 3

Focus on solving the system of equations xy=240 and x+y=32 first. Once you have x and y, separately, and make sure that x>y, you can then write x-y.