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solve the equation using the quadratic formula: x^2+4=4x
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\[ x^2+4 =4 x\\ x^2-4 x + 4 =0\\ (x-2)^2=0\\ x=2 \]
Do it with the quadratic formula and confirm the answer above.
I need help with setting up the quadratic formula i can't get it set up right.
\[ x^2-4 x + 4=0\\ a=1; b=-4; c=4\\ \Delta = b^2-4 a c= 16- 4(1)(4)=0\\ x=\frac { -b\pm \sqrt \Delta}{2 a}=\frac { 4\pm 0}{2}=2 \]
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