Question

Find trignometric function of 5 pi /6

Answer 1

u may use below :

\(\sin (\pi-x) = \sin (x)\)
\(\cos (\pi-x) = -\cos (x)\)

Answer 2

i got it i made a unit circle

Answer 3

thats clever ^

Answer 4

\[\sin \frac{ 5π }{ 6 }=\sin \frac{ (6-1)π }{ 6 }=\sin \left( π-\frac{ π }{ 6 } \right)=\sin \left( \frac{ π }{ 6 } \right)=1/2\]
\[\cos ^{2}x+\sin^{2}x=1 <=> cosx=\pm \sqrt{1-\sin^{2}x} =\pm \sqrt{1-\frac{ 1 }{ 4 }}=\pm \frac{ \sqrt{3} }{ 2 }\]
\[tanx=\frac{ sinx }{ cosx }= \frac{ \frac{ 1 }{ 2 } }{ \frac{\pm \sqrt{3} }{ 2 } }=\pm \frac{ \sqrt{3} }{ 3 }\]
\[cotx=\tan^{-1} x=\pm \sqrt{3}\]
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Answer 5

Nice :)