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Physics 19 Online
OpenStudy (anonymous):

A positive test charge of 3.2 * 10^(-4) C is in an electric field that exerts a force of 2.5 * 10^(5) N on it. What is the magnitude of the electric field at the location of the test charge?

OpenStudy (anonymous):

magnitude of the electric:\[E=\frac{ F }{q }=\frac{2.5 * 10^{5} N }{3.2 * 10^{-4} C }=... \]

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