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Mathematics 12 Online
OpenStudy (anonymous):

Solve; 15x^2=20x

OpenStudy (anonymous):

x = 4/3 x = 0

OpenStudy (anonymous):

\[15x^2=20x\] \[15x^2-20x=0\] \[5x(3x-4)=0\] \[3x-4=0\] \[3x=4\] \[x=\frac{ 4 }{ 3 }\] \[5x=0\] \[x=0\] So: \[x=0\] & \[x=\frac{ 4 }{ 3 }\]

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