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Mathematics 10 Online
OpenStudy (anonymous):

Solve on the interval (0,2pi): sec^2x-1=0

OpenStudy (anonymous):

sec^2x-1 = 0 tan^2x = 0 tanx = 0

OpenStudy (anonymous):

tanx = 0 when x = 0,pi,2pi

OpenStudy (anonymous):

Thanks!

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